Five particles of mass 2 kg are attached to the rim of a circular disc of radius 0.1 m and negligible mass. Moment of inertia of the system about the axis passing through the centre of the disc and perpendicular to its plane is :
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The moment of inertial of the given system that contains 5 particles each of mass 2 kg on the rim of circular disc of radius 0.1 m and of negligible mass is given by
= MI of disc + MI of particles
Since, the mass of the disc is negligible therefore, MI of the system = MI of particles
= 5 × 2 × (0.1) 2 = 0.1 kg m 2
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